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64133300333146 = 21111003264941381
BaseRepresentation
bin11101001010100001100101…
…00101011010101001011010
322102002002020222011202111011
432211100302211122221122
531401224444341130041
6344222233105124134
716336322653166452
oct1645206245325132
9272062228152434
1064133300333146
11194868640a4a60
12723956862964a
1329a298a2195a5
1411ba0d55a6d62
157633c34dce81
hex3a543295aa5a

64133300333146 has 16 divisors (see below), whose sum is σ = 104954938831008. Its totient is φ = 29148850627600.

The previous prime is 64133300333131. The next prime is 64133300333257.

64133300333146 is nontrivially palindromic in base 10.

It is a super-2 number, since 2×641333003331462 (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 64133300333099 and 64133300333108.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 132228625 + ... + 132712756.

It is an arithmetic number, because the mean of its divisors is an integer number (6559683676938).

Almost surely, 264133300333146 is an apocalyptic number.

64133300333146 is a deficient number, since it is larger than the sum of its proper divisors (40821638497862).

64133300333146 is a wasteful number, since it uses less digits than its factorization.

64133300333146 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 264952397.

The product of its (nonzero) digits is 419904, while the sum is 40.

It can be divided in two parts, 64133300 and 333146, that added together give a palindrome (64466446).

The spelling of 64133300333146 in words is "sixty-four trillion, one hundred thirty-three billion, three hundred million, three hundred thirty-three thousand, one hundred forty-six".

Divisors: 1 2 11 22 11003 22006 121033 242066 264941381 529882762 2914355191 5828710382 2915150015143 5830300030286 32066650166573 64133300333146