Base | Representation |
---|---|
bin | 1011111100100011… |
… | …01010101111101111 |
3 | 121112222011222111211 |
4 | 11332101222233233 |
5 | 101113330344142 |
6 | 2540224055251 |
7 | 314635042333 |
oct | 57621525757 |
9 | 17488158454 |
10 | 6413528047 |
11 | 27a12a6603 |
12 | 12aba64527 |
13 | 7b2965a14 |
14 | 44bad57c3 |
15 | 2780be917 |
hex | 17e46abef |
6413528047 has 4 divisors (see below), whose sum is σ = 6414032080. Its totient is φ = 6413024016.
The previous prime is 6413527997. The next prime is 6413528059. The reversal of 6413528047 is 7408253146.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-6413528047 is a prime.
It is a super-2 number, since 2×64135280472 = 82266684019311268418, which contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (6413528347) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 232422 + ... + 258547.
It is an arithmetic number, because the mean of its divisors is an integer number (1603508020).
Almost surely, 26413528047 is an apocalyptic number.
6413528047 is a deficient number, since it is larger than the sum of its proper divisors (504033).
6413528047 is a wasteful number, since it uses less digits than its factorization.
6413528047 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 504032.
The product of its (nonzero) digits is 161280, while the sum is 40.
The square root of 6413528047 is about 80084.5056612076. The cubic root of 6413528047 is about 1857.9427718136.
The spelling of 6413528047 in words is "six billion, four hundred thirteen million, five hundred twenty-eight thousand, forty-seven".
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