Base | Representation |
---|---|
bin | 101110101010110011001… |
… | …0010010010000101101101 |
3 | 211201011220210222000122011 |
4 | 1131111212102102011231 |
5 | 1320042040133213040 |
6 | 21350333051121221 |
7 | 1231255301330260 |
oct | 135254622220555 |
9 | 24634823860564 |
10 | 6414102241645 |
11 | 205322955570a |
12 | 877119a43211 |
13 | 376b02526c07 |
14 | 182630c80cd7 |
15 | b1ca395d3ea |
hex | 5d56649216d |
6414102241645 has 16 divisors (see below), whose sum is σ = 8796669004800. Its totient is φ = 4398148571904.
The previous prime is 6414102241627. The next prime is 6414102241691. The reversal of 6414102241645 is 5461422014146.
It is a cyclic number.
It is not a de Polignac number, because 6414102241645 - 213 = 6414102233453 is a prime.
It is a super-3 number, since 3×64141022416453 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 6414102241598 and 6414102241607.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 236220 + ... + 3589429.
It is an arithmetic number, because the mean of its divisors is an integer number (549791812800).
Almost surely, 26414102241645 is an apocalyptic number.
It is an amenable number.
6414102241645 is a deficient number, since it is larger than the sum of its proper divisors (2382566763155).
6414102241645 is a wasteful number, since it uses less digits than its factorization.
6414102241645 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3873564.
The product of its (nonzero) digits is 184320, while the sum is 40.
The spelling of 6414102241645 in words is "six trillion, four hundred fourteen billion, one hundred two million, two hundred forty-one thousand, six hundred forty-five".
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