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64157031253173 = 321385677084391
BaseRepresentation
bin11101001011001101110010…
…00011101100010010110101
322102011100111211002101212010
432211212321003230102311
531402122100000100143
6344241155553114433
716341123020530305
oct1645467103542265
9272140454071763
1064157031253173
1119495931632461
12724208bb58a19
1329a4c9c8527c1
1411bb30719b605
15763d11a7ba33
hex3a59b90ec4b5

64157031253173 has 4 divisors (see below), whose sum is σ = 85542708337568. Its totient is φ = 42771354168780.

The previous prime is 64157031253121. The next prime is 64157031253193. The reversal of 64157031253173 is 37135213075146.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 64157031253173 - 214 = 64157031236789 is a prime.

It is a super-2 number, since 2×641570312531732 (a number of 28 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (64157031253193) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10692838542193 + ... + 10692838542198.

It is an arithmetic number, because the mean of its divisors is an integer number (21385677084392).

Almost surely, 264157031253173 is an apocalyptic number.

It is an amenable number.

64157031253173 is a deficient number, since it is larger than the sum of its proper divisors (21385677084395).

64157031253173 is a wasteful number, since it uses less digits than its factorization.

64157031253173 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 21385677084394.

The product of its (nonzero) digits is 1587600, while the sum is 48.

The spelling of 64157031253173 in words is "sixty-four trillion, one hundred fifty-seven billion, thirty-one million, two hundred fifty-three thousand, one hundred seventy-three".

Divisors: 1 3 21385677084391 64157031253173