Base | Representation |
---|---|
bin | 10010101110010001011… |
… | …10010100100111000011 |
3 | 2021111111220202220002211 |
4 | 21113020232110213003 |
5 | 41020003313311342 |
6 | 1211311443122551 |
7 | 64323004224331 |
oct | 11271056244703 |
9 | 2244456686084 |
10 | 643317713347 |
11 | 2289140947a1 |
12 | a4819973457 |
13 | 4888418475a |
14 | 231cb31cb51 |
15 | 11b02c55c17 |
hex | 95c8b949c3 |
643317713347 has 4 divisors (see below), whose sum is σ = 645709229280. Its totient is φ = 640926197416.
The previous prime is 643317713333. The next prime is 643317713369. The reversal of 643317713347 is 743317713346.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 643317713347 - 27 = 643317713219 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 643317713347.
It is not an unprimeable number, because it can be changed into a prime (643317713377) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1195757563 + ... + 1195758100.
It is an arithmetic number, because the mean of its divisors is an integer number (161427307320).
Almost surely, 2643317713347 is an apocalyptic number.
643317713347 is a deficient number, since it is larger than the sum of its proper divisors (2391515933).
643317713347 is a wasteful number, since it uses less digits than its factorization.
643317713347 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2391515932.
The product of its digits is 2667168, while the sum is 49.
Subtracting 643317713347 from its reverse (743317713346), we obtain a palindrome (99999999999).
The spelling of 643317713347 in words is "six hundred forty-three billion, three hundred seventeen million, seven hundred thirteen thousand, three hundred forty-seven".
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