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643317713347 = 2692391515663
BaseRepresentation
bin10010101110010001011…
…10010100100111000011
32021111111220202220002211
421113020232110213003
541020003313311342
61211311443122551
764323004224331
oct11271056244703
92244456686084
10643317713347
112289140947a1
12a4819973457
134888418475a
14231cb31cb51
1511b02c55c17
hex95c8b949c3

643317713347 has 4 divisors (see below), whose sum is σ = 645709229280. Its totient is φ = 640926197416.

The previous prime is 643317713333. The next prime is 643317713369. The reversal of 643317713347 is 743317713346.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 643317713347 - 27 = 643317713219 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 643317713347.

It is not an unprimeable number, because it can be changed into a prime (643317713377) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1195757563 + ... + 1195758100.

It is an arithmetic number, because the mean of its divisors is an integer number (161427307320).

Almost surely, 2643317713347 is an apocalyptic number.

643317713347 is a deficient number, since it is larger than the sum of its proper divisors (2391515933).

643317713347 is a wasteful number, since it uses less digits than its factorization.

643317713347 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2391515932.

The product of its digits is 2667168, while the sum is 49.

Subtracting 643317713347 from its reverse (743317713346), we obtain a palindrome (99999999999).

The spelling of 643317713347 in words is "six hundred forty-three billion, three hundred seventeen million, seven hundred thirteen thousand, three hundred forty-seven".

Divisors: 1 269 2391515663 643317713347