Base | Representation |
---|---|
bin | 111100000000011001… |
… | …100100101110000101 |
3 | 20011022022200202211201 |
4 | 330000121210232011 |
5 | 2023423342312240 |
6 | 45333240302501 |
7 | 4440444164224 |
oct | 740031445605 |
9 | 204268622751 |
10 | 64431213445 |
11 | 25363816335 |
12 | 105a1a71a31 |
13 | 60ca7cb591 |
14 | 31931b4cbb |
15 | 1a217a4d9a |
hex | f00664b85 |
64431213445 has 4 divisors (see below), whose sum is σ = 77317456140. Its totient is φ = 51544970752.
The previous prime is 64431213437. The next prime is 64431213467. The reversal of 64431213445 is 54431213446.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 10836185409 + 53595028036 = 104097^2 + 231506^2 .
It is a cyclic number.
It is not a de Polignac number, because 64431213445 - 23 = 64431213437 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6443121340 + ... + 6443121349.
It is an arithmetic number, because the mean of its divisors is an integer number (19329364035).
Almost surely, 264431213445 is an apocalyptic number.
It is an amenable number.
64431213445 is a deficient number, since it is larger than the sum of its proper divisors (12886242695).
64431213445 is a wasteful number, since it uses less digits than its factorization.
64431213445 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12886242694.
The product of its digits is 138240, while the sum is 37.
Subtracting from 64431213445 its reverse (54431213446), we obtain a palindrome (9999999999).
The spelling of 64431213445 in words is "sixty-four billion, four hundred thirty-one million, two hundred thirteen thousand, four hundred forty-five".
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