Base | Representation |
---|---|
bin | 101110111001010000010… |
… | …0010110110011010100111 |
3 | 211211011001012022210121211 |
4 | 1131302200202312122213 |
5 | 1321044123433344333 |
6 | 21412505233052251 |
7 | 1233434454526636 |
oct | 135624042663247 |
9 | 24734035283554 |
10 | 6445144434343 |
11 | 206540901051a |
12 | 8811419b7087 |
13 | 379a0b7aca84 |
14 | 183d3789b51d |
15 | b29bdceeecd |
hex | 5dca08b66a7 |
6445144434343 has 4 divisors (see below), whose sum is σ = 6463718337960. Its totient is φ = 6426570530728.
The previous prime is 6445144434319. The next prime is 6445144434347. The reversal of 6445144434343 is 3434344415446.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-6445144434343 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (6445144434347) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9286951288 + ... + 9286951981.
It is an arithmetic number, because the mean of its divisors is an integer number (1615929584490).
Almost surely, 26445144434343 is an apocalyptic number.
6445144434343 is a deficient number, since it is larger than the sum of its proper divisors (18573903617).
6445144434343 is a wasteful number, since it uses less digits than its factorization.
6445144434343 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 18573903616.
The product of its digits is 13271040, while the sum is 49.
Adding to 6445144434343 its reverse (3434344415446), we get a palindrome (9879488849789).
The spelling of 6445144434343 in words is "six trillion, four hundred forty-five billion, one hundred forty-four million, four hundred thirty-four thousand, three hundred forty-three".
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