Base | Representation |
---|---|
bin | 11101010110110100111110… |
… | …10111001001001010001101 |
3 | 22110120111101212120200112221 |
4 | 32223122133113021022031 |
5 | 31430141223204244203 |
6 | 345144344242055341 |
7 | 16412006441020231 |
oct | 1653323727111215 |
9 | 273514355520487 |
10 | 64556032103053 |
11 | 1962a072171557 |
12 | 72a748464a551 |
13 | 2a037b919074a |
14 | 11d27587945c1 |
15 | 76e3b58b0abd |
hex | 3ab69f5c928d |
64556032103053 has 4 divisors (see below), whose sum is σ = 64619384441760. Its totient is φ = 64492679764348.
The previous prime is 64556032103041. The next prime is 64556032103089. The reversal of 64556032103053 is 35030123065546.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 64556032103053 - 225 = 64555998548621 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (64556032103093) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31676167825 + ... + 31676169862.
It is an arithmetic number, because the mean of its divisors is an integer number (16154846110440).
Almost surely, 264556032103053 is an apocalyptic number.
It is an amenable number.
64556032103053 is a deficient number, since it is larger than the sum of its proper divisors (63352338707).
64556032103053 is a wasteful number, since it uses less digits than its factorization.
64556032103053 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 63352338706.
The product of its (nonzero) digits is 972000, while the sum is 43.
Adding to 64556032103053 its reverse (35030123065546), we get a palindrome (99586155168599).
The spelling of 64556032103053 in words is "sixty-four trillion, five hundred fifty-six billion, thirty-two million, one hundred three thousand, fifty-three".
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