Base | Representation |
---|---|
bin | 10010110011010000000… |
… | …01101101111011000111 |
3 | 2021202102011212011210120 |
4 | 21121220001231323013 |
5 | 41040442014000421 |
6 | 1212432555353023 |
7 | 64446146406204 |
oct | 11315001557307 |
9 | 2252364764716 |
10 | 645990375111 |
11 | 229a657a9074 |
12 | a5244a52773 |
13 | 48bbbab8913 |
14 | 233a2276cab |
15 | 11c0c6da8c6 |
hex | 966806dec7 |
645990375111 has 4 divisors (see below), whose sum is σ = 861320500152. Its totient is φ = 430660250072.
The previous prime is 645990375071. The next prime is 645990375137. The reversal of 645990375111 is 111573099546.
645990375111 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 645990375111 - 29 = 645990374599 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (645990175111) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 107665062516 + ... + 107665062521.
It is an arithmetic number, because the mean of its divisors is an integer number (215330125038).
Almost surely, 2645990375111 is an apocalyptic number.
645990375111 is a deficient number, since it is larger than the sum of its proper divisors (215330125041).
645990375111 is a wasteful number, since it uses less digits than its factorization.
645990375111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 215330125040.
The product of its (nonzero) digits is 1020600, while the sum is 51.
The spelling of 645990375111 in words is "six hundred forty-five billion, nine hundred ninety million, three hundred seventy-five thousand, one hundred eleven".
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