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65053113 = 321684371
BaseRepresentation
bin1111100000101…
…0000110111001
311112102001002120
43320022012321
5113123144423
610242151453
71416641136
oct370120671
9145361076
1065053113
11337a2404
1219952589
1310628c88
1488d558d
155a9eee3
hex3e0a1b9

65053113 has 4 divisors (see below), whose sum is σ = 86737488. Its totient is φ = 43368740.

The previous prime is 65053091. The next prime is 65053139. The reversal of 65053113 is 31135056.

65053113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 65053113 - 217 = 64922041 is a prime.

It is not an unprimeable number, because it can be changed into a prime (65053193) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10842183 + ... + 10842188.

It is an arithmetic number, because the mean of its divisors is an integer number (21684372).

Almost surely, 265053113 is an apocalyptic number.

It is an amenable number.

65053113 is a deficient number, since it is larger than the sum of its proper divisors (21684375).

65053113 is a wasteful number, since it uses less digits than its factorization.

65053113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 21684374.

The product of its (nonzero) digits is 1350, while the sum is 24.

The square root of 65053113 is about 8065.5510041162. The cubic root of 65053113 is about 402.1820603037.

Adding to 65053113 its reverse (31135056), we get a palindrome (96188169).

The spelling of 65053113 in words is "sixty-five million, fifty-three thousand, one hundred thirteen".

Divisors: 1 3 21684371 65053113