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65112031149703 = 2391307208443211
BaseRepresentation
bin11101100111000000100110…
…11111001011111010000111
322112112122112101212201100021
432303200103133023322013
532013243414433242303
6350252015411200011
716500121554650356
oct1663402337137207
9275478471781307
1065112031149703
111982394813159a
1273771935a6007
132a44065ba2085
141211620d4999d
1577daa7883ebd
hex3b38137cbe87

65112031149703 has 8 divisors (see below), whose sum is σ = 65434493111040. Its totient is φ = 64789986077880.

The previous prime is 65112031149667. The next prime is 65112031149707. The reversal of 65112031149703 is 30794113021156.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-65112031149703 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 65112031149703.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (65112031149707) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 103909233 + ... + 104533978.

It is an arithmetic number, because the mean of its divisors is an integer number (8179311638880).

Almost surely, 265112031149703 is an apocalyptic number.

65112031149703 is a deficient number, since it is larger than the sum of its proper divisors (322461961337).

65112031149703 is a wasteful number, since it uses less digits than its factorization.

65112031149703 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 208444757.

The product of its (nonzero) digits is 136080, while the sum is 43.

The spelling of 65112031149703 in words is "sixty-five trillion, one hundred twelve billion, thirty-one million, one hundred forty-nine thousand, seven hundred three".

Divisors: 1 239 1307 312373 208443211 49817927429 272435276777 65112031149703