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6511460345053 = 53120312257951
BaseRepresentation
bin101111011000001000101…
…0001111110010011011101
3212001111012212102010001221
41132300101101332103131
51323140432322020203
621503153521133341
71241303025500326
oct136602121762335
925044185363057
106511460345053
11209054967a7a4
12891b6aa8a251
133830498b4821
141872290b544d
15b45a0c8dabd
hex5ec1147e4dd

6511460345053 has 4 divisors (see below), whose sum is σ = 6511473134208. Its totient is φ = 6511447555900.

The previous prime is 6511460345017. The next prime is 6511460345059. The reversal of 6511460345053 is 3505430641156.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 6511460345053 - 229 = 6510923474141 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (6511460345059) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5597773 + ... + 6660178.

It is an arithmetic number, because the mean of its divisors is an integer number (1627868283552).

Almost surely, 26511460345053 is an apocalyptic number.

It is an amenable number.

6511460345053 is a deficient number, since it is larger than the sum of its proper divisors (12789155).

6511460345053 is a wasteful number, since it uses less digits than its factorization.

6511460345053 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12789154.

The product of its (nonzero) digits is 648000, while the sum is 43.

The spelling of 6511460345053 in words is "six trillion, five hundred eleven billion, four hundred sixty million, three hundred forty-five thousand, fifty-three".

Divisors: 1 531203 12257951 6511460345053