Base | Representation |
---|---|
bin | 111100110000100101… |
… | …110001111100100001 |
3 | 20020101200001010221022 |
4 | 330300211301330201 |
5 | 2032102332012323 |
6 | 45545401335225 |
7 | 4466462316320 |
oct | 746045617441 |
9 | 206350033838 |
10 | 65239719713 |
11 | 25739137033 |
12 | 10788797515 |
13 | 61c916c15c |
14 | 322c7160b7 |
15 | 1a6c75c4c8 |
hex | f30971f21 |
65239719713 has 4 divisors (see below), whose sum is σ = 74559679680. Its totient is φ = 55919759748.
The previous prime is 65239719709. The next prime is 65239719767. The reversal of 65239719713 is 31791793256.
65239719713 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 65239719713 - 22 = 65239719709 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (65239719313) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4659979973 + ... + 4659979986.
It is an arithmetic number, because the mean of its divisors is an integer number (18639919920).
Almost surely, 265239719713 is an apocalyptic number.
It is an amenable number.
65239719713 is a deficient number, since it is larger than the sum of its proper divisors (9319959967).
65239719713 is an equidigital number, since it uses as much as digits as its factorization.
65239719713 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9319959966.
The product of its digits is 2143260, while the sum is 53.
The spelling of 65239719713 in words is "sixty-five billion, two hundred thirty-nine million, seven hundred nineteen thousand, seven hundred thirteen".
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