Base | Representation |
---|---|
bin | 111100110101000001… |
… | …100111001001010101 |
3 | 20020120212001021221110 |
4 | 330311001213021111 |
5 | 2032230403434443 |
6 | 50001020205233 |
7 | 4501354616451 |
oct | 746501471125 |
9 | 206525037843 |
10 | 65314124373 |
11 | 25777136393 |
12 | 107a9699819 |
13 | 620b6c0794 |
14 | 3238563661 |
15 | 1a74058233 |
hex | f35067255 |
65314124373 has 4 divisors (see below), whose sum is σ = 87085499168. Its totient is φ = 43542749580.
The previous prime is 65314124371. The next prime is 65314124383. The reversal of 65314124373 is 37342141356.
65314124373 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 65314124373 - 21 = 65314124371 is a prime.
It is a super-2 number, since 2×653141243732 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (65314124371) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10885687393 + ... + 10885687398.
It is an arithmetic number, because the mean of its divisors is an integer number (21771374792).
Almost surely, 265314124373 is an apocalyptic number.
It is an amenable number.
65314124373 is a deficient number, since it is larger than the sum of its proper divisors (21771374795).
65314124373 is a wasteful number, since it uses less digits than its factorization.
65314124373 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 21771374794.
The product of its digits is 181440, while the sum is 39.
The spelling of 65314124373 in words is "sixty-five billion, three hundred fourteen million, one hundred twenty-four thousand, three hundred seventy-three".
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