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65352461341 = 226512885191
BaseRepresentation
bin111100110111010011…
…110110110000011101
320020200112012000101011
4330313103312300131
52032320212230331
650004510015221
74502331520156
oct746723666035
9206615160334
1065352461341
1125796840532
12107ba4a7511
13621662438b
14323d6a292d
151a775cc3b1
hexf374f6c1d

65352461341 has 4 divisors (see below), whose sum is σ = 65355369184. Its totient is φ = 65349553500.

The previous prime is 65352461333. The next prime is 65352461353. The reversal of 65352461341 is 14316425356.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 65352461341 - 23 = 65352461333 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 65352461294 and 65352461303.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (65352461371) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1419945 + ... + 1465246.

It is an arithmetic number, because the mean of its divisors is an integer number (16338842296).

Almost surely, 265352461341 is an apocalyptic number.

It is an amenable number.

65352461341 is a deficient number, since it is larger than the sum of its proper divisors (2907843).

65352461341 is a wasteful number, since it uses less digits than its factorization.

65352461341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2907842.

The product of its digits is 259200, while the sum is 40.

Adding to 65352461341 its reverse (14316425356), we get a palindrome (79668886697).

The spelling of 65352461341 in words is "sixty-five billion, three hundred fifty-two million, four hundred sixty-one thousand, three hundred forty-one".

Divisors: 1 22651 2885191 65352461341