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6551022122017 = 50313023900839
BaseRepresentation
bin101111101010100011101…
…0110001011010000100001
3212012021022222212121120121
41133111013112023100201
51324312443130401032
621533255323240241
71244203302162052
oct137250726132041
925167288777517
106551022122017
1120a630022633a
12899770079081
133869b2c319c9
141890dd3ac729
15b5619061a97
hex5f54758b421

6551022122017 has 4 divisors (see below), whose sum is σ = 6564046023360. Its totient is φ = 6537998220676.

The previous prime is 6551022121999. The next prime is 6551022122023. The reversal of 6551022122017 is 7102212201556.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-6551022122017 is a prime.

It is a super-3 number, since 3×65510221220173 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (6551022122077) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6511949917 + ... + 6511950922.

It is an arithmetic number, because the mean of its divisors is an integer number (1641011505840).

Almost surely, 26551022122017 is an apocalyptic number.

It is an amenable number.

6551022122017 is a deficient number, since it is larger than the sum of its proper divisors (13023901343).

6551022122017 is a wasteful number, since it uses less digits than its factorization.

6551022122017 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13023901342.

The product of its (nonzero) digits is 16800, while the sum is 34.

The spelling of 6551022122017 in words is "six trillion, five hundred fifty-one billion, twenty-two million, one hundred twenty-two thousand, seventeen".

Divisors: 1 503 13023900839 6551022122017