Base | Representation |
---|---|
bin | 1111110000110… |
… | …0111001111101 |
3 | 11121101220012011 |
4 | 3330030321331 |
5 | 113411110044 |
6 | 10321011221 |
7 | 1431644464 |
oct | 374147175 |
9 | 147356164 |
10 | 66113149 |
11 | 34356873 |
12 | 1a183b11 |
13 | 1090a60b |
14 | 8acd9db |
15 | 5c0e134 |
hex | 3f0ce7d |
66113149 has 4 divisors (see below), whose sum is σ = 66376800. Its totient is φ = 65849500.
The previous prime is 66113147. The next prime is 66113189. The reversal of 66113149 is 94131166.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 66113149 - 21 = 66113147 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 66113149.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (66113143) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 131449 + ... + 131950.
It is an arithmetic number, because the mean of its divisors is an integer number (16594200).
Almost surely, 266113149 is an apocalyptic number.
It is an amenable number.
66113149 is a deficient number, since it is larger than the sum of its proper divisors (263651).
66113149 is a wasteful number, since it uses less digits than its factorization.
66113149 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 263650.
The product of its digits is 3888, while the sum is 31.
The square root of 66113149 is about 8130.9992620834. Note that the first 3 decimals coincide. The cubic root of 66113149 is about 404.3548107535.
The spelling of 66113149 in words is "sixty-six million, one hundred thirteen thousand, one hundred forty-nine".
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