6643913004151 has 4 divisors (see below), whose sum is σ = 6873013452600. Its totient is φ = 6414812555704.

The previous prime is 6643913004149. The next prime is 6643913004161. The reversal of 6643913004151 is 1514003193466.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 6643913004151 - 2¹ = 6643913004149 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 6643913004098 and 6643913004107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (6643913004161) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 114550224181 + ... + 114550224238.

It is an arithmetic number, because the mean of its divisors is an integer number (1718253363150).

Almost surely, 2^{6643913004151} is an apocalyptic number.

6643913004151 is a deficient number, since it is larger than the sum of its proper divisors (229100448449).

6643913004151 is a wasteful number, since it uses less digits than its factorization.

6643913004151 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 229100448448.

The product of its (nonzero) digits is 233280, while the sum is 43.

The spelling of 6643913004151 in words is "six trillion, six hundred forty-three billion, nine hundred thirteen million, four thousand, one hundred fifty-one".