Base | Representation |
---|---|
bin | 11110010000000100110101… |
… | …11101010001100100000011 |
3 | 22201112112121221212102121120 |
4 | 33020002122331101210003 |
5 | 32204403203112000220 |
6 | 353252134015323323 |
7 | 20004063162534300 |
oct | 1710023275214403 |
9 | 281475557772546 |
10 | 66523053234435 |
11 | 1a2182a5331216 |
12 | 7564743b20543 |
13 | 2b17135166875 |
14 | 125da393340a7 |
15 | 7a563d496a40 |
hex | 3c809af51903 |
66523053234435 has 24 divisors (see below), whose sum is σ = 123814335817296. Its totient is φ = 30410538621120.
The previous prime is 66523053234383. The next prime is 66523053234439. The reversal of 66523053234435 is 53443235032566.
It is not a de Polignac number, because 66523053234435 - 26 = 66523053234371 is a prime.
It is a super-2 number, since 2×665230532344352 (a number of 28 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (66523053234439) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 45253776976 + ... + 45253778445.
It is an arithmetic number, because the mean of its divisors is an integer number (5158930659054).
Almost surely, 266523053234435 is an apocalyptic number.
66523053234435 is a deficient number, since it is larger than the sum of its proper divisors (57291282582861).
66523053234435 is a wasteful number, since it uses less digits than its factorization.
66523053234435 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 90507555443 (or 90507555436 counting only the distinct ones).
The product of its (nonzero) digits is 23328000, while the sum is 51.
The spelling of 66523053234435 in words is "sixty-six trillion, five hundred twenty-three billion, fifty-three million, two hundred thirty-four thousand, four hundred thirty-five".
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