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68172113 = 307222059
BaseRepresentation
bin1000001000000…
…11100101010001
311202021111120002
410010003211101
5114423001423
610433055345
71455311342
oct404034521
9152244502
1068172113
1135532799
121a9b7555
131117b839
1490a80c9
155eb9228
hex4103951

68172113 has 4 divisors (see below), whose sum is σ = 68394480. Its totient is φ = 67949748.

The previous prime is 68172103. The next prime is 68172149. The reversal of 68172113 is 31127186.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31127186 = 215563593.

It is a cyclic number.

It is not a de Polignac number, because 68172113 - 218 = 67909969 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (68172103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 110723 + ... + 111336.

It is an arithmetic number, because the mean of its divisors is an integer number (17098620).

Almost surely, 268172113 is an apocalyptic number.

It is an amenable number.

68172113 is a deficient number, since it is larger than the sum of its proper divisors (222367).

68172113 is a wasteful number, since it uses less digits than its factorization.

68172113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 222366.

The product of its digits is 2016, while the sum is 29.

The square root of 68172113 is about 8256.6405395899. The cubic root of 68172113 is about 408.5095857008.

Adding to 68172113 its reverse (31127186), we get a palindrome (99299299).

The spelling of 68172113 in words is "sixty-eight million, one hundred seventy-two thousand, one hundred thirteen".

Divisors: 1 307 222059 68172113