Base | Representation |
---|---|
bin | 111111100111100111… |
… | …001101011110001011 |
3 | 20112022122221001200220 |
4 | 333213213031132023 |
5 | 2104344420401011 |
6 | 51214211201123 |
7 | 4635536116566 |
oct | 774747153613 |
9 | 215278831626 |
10 | 68310325131 |
11 | 26a74441364 |
12 | 112a4ba61a3 |
13 | 6598374939 |
14 | 344045b4dd |
15 | 1b9c0eb506 |
hex | fe79cd78b |
68310325131 has 16 divisors (see below), whose sum is σ = 95287062528. Its totient is φ = 43484168000.
The previous prime is 68310325129. The next prime is 68310325133. The reversal of 68310325131 is 13152301386.
It is an interprime number because it is at equal distance from previous prime (68310325129) and next prime (68310325133).
It is a cyclic number.
It is not a de Polignac number, because 68310325131 - 21 = 68310325129 is a prime.
It is a super-2 number, since 2×683103251312 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 68310325092 and 68310325101.
It is not an unprimeable number, because it can be changed into a prime (68310325133) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5902395 + ... + 5913956.
It is an arithmetic number, because the mean of its divisors is an integer number (5955441408).
Almost surely, 268310325131 is an apocalyptic number.
68310325131 is a deficient number, since it is larger than the sum of its proper divisors (26976737397).
68310325131 is a wasteful number, since it uses less digits than its factorization.
68310325131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11816442.
The product of its (nonzero) digits is 12960, while the sum is 33.
The spelling of 68310325131 in words is "sixty-eight billion, three hundred ten million, three hundred twenty-five thousand, one hundred thirty-one".
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