Base | Representation |
---|---|
bin | 111111101001011100… |
… | …101110110010110111 |
3 | 20112101210220020102111 |
4 | 333221130232302313 |
5 | 2104430312214341 |
6 | 51221231351451 |
7 | 4636362020113 |
oct | 775134566267 |
9 | 215353806374 |
10 | 68341132471 |
11 | 26a8a873377 |
12 | 112b3382587 |
13 | 65a1870231 |
14 | 344459a743 |
15 | 1b9eb84681 |
hex | fe972ecb7 |
68341132471 has 8 divisors (see below), whose sum is σ = 72463132080. Its totient is φ = 64271642688.
The previous prime is 68341132469. The next prime is 68341132493. The reversal of 68341132471 is 17423114386.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 68341132471 - 21 = 68341132469 is a prime.
It is a super-3 number, since 3×683411324713 (a number of 33 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (68341132441) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 13124776 + ... + 13129981.
It is an arithmetic number, because the mean of its divisors is an integer number (9057891510).
Almost surely, 268341132471 is an apocalyptic number.
68341132471 is a deficient number, since it is larger than the sum of its proper divisors (4121999609).
68341132471 is a wasteful number, since it uses less digits than its factorization.
68341132471 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 26254913.
The product of its digits is 96768, while the sum is 40.
The spelling of 68341132471 in words is "sixty-eight billion, three hundred forty-one million, one hundred thirty-two thousand, four hundred seventy-one".
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