Base | Representation |
---|---|
bin | 110001110000010010110… |
… | …0100011000000110001111 |
3 | 220012201122012000102211220 |
4 | 1203200211210120012033 |
5 | 1344014132331244421 |
6 | 22313233432414423 |
7 | 1304021264615604 |
oct | 143404544300617 |
9 | 26181565012756 |
10 | 6838218228111 |
11 | 21a7087a10636 |
12 | 925361547413 |
13 | 3a7ac21b171a |
14 | 198d85c326ab |
15 | bcd276093c6 |
hex | 6382591818f |
6838218228111 has 8 divisors (see below), whose sum is σ = 9124730797440. Its totient is φ = 4555258905432.
The previous prime is 6838218228103. The next prime is 6838218228113. The reversal of 6838218228111 is 1118228128386.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 6838218228111 - 23 = 6838218228103 is a prime.
It is a super-3 number, since 3×68382182281113 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (6838218228113) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 888307171 + ... + 888314868.
It is an arithmetic number, because the mean of its divisors is an integer number (1140591349680).
Almost surely, 26838218228111 is an apocalyptic number.
6838218228111 is a deficient number, since it is larger than the sum of its proper divisors (2286512569329).
6838218228111 is a wasteful number, since it uses less digits than its factorization.
6838218228111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1776623325.
The product of its digits is 589824, while the sum is 51.
The spelling of 6838218228111 in words is "six trillion, eight hundred thirty-eight billion, two hundred eighteen million, two hundred twenty-eight thousand, one hundred eleven".
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