Base | Representation |
---|---|
bin | 110010001010011011010… |
… | …1000010010011101111111 |
3 | 220102002111100020010111000 |
4 | 1210110312220102131333 |
5 | 1400424101243304101 |
6 | 22355114324301343 |
7 | 1311046101635412 |
oct | 144246650223577 |
9 | 26362440203430 |
10 | 6894339041151 |
11 | 2218966721061 |
12 | 934204241853 |
13 | 3b019706a1c3 |
14 | 19b98b41db79 |
15 | be50e4ed486 |
hex | 64536a1277f |
6894339041151 has 16 divisors (see below), whose sum is σ = 10336893880320. Its totient is φ = 4540849808760.
The previous prime is 6894339041129. The next prime is 6894339041179. The reversal of 6894339041151 is 1511409334986.
6894339041151 is a `hidden beast` number, since 6 + 8 + 9 + 433 + 90 + 4 + 115 + 1 = 666.
It is not a de Polignac number, because 6894339041151 - 215 = 6894339008383 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (6894339041351) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1538226015 + ... + 1538230496.
It is an arithmetic number, because the mean of its divisors is an integer number (646055867520).
Almost surely, 26894339041151 is an apocalyptic number.
6894339041151 is a deficient number, since it is larger than the sum of its proper divisors (3442554839169).
6894339041151 is a wasteful number, since it uses less digits than its factorization.
6894339041151 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3076456603 (or 3076456597 counting only the distinct ones).
The product of its (nonzero) digits is 2799360, while the sum is 54.
The spelling of 6894339041151 in words is "six trillion, eight hundred ninety-four billion, three hundred thirty-nine million, forty-one thousand, one hundred fifty-one".
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