Base | Representation |
---|---|
bin | 100001010000001011… |
… | …0110100110110011111 |
3 | 20211022200011110101212 |
4 | 1002200112310312133 |
5 | 2132221403034233 |
6 | 52445532055035 |
7 | 5105413261205 |
oct | 1024026646637 |
9 | 224280143355 |
10 | 71409814943 |
11 | 28314a84995 |
12 | 11a0b00447b |
13 | 697055168c |
14 | 3655d61075 |
15 | 1cce293a48 |
hex | 10a05b4d9f |
71409814943 has 4 divisors (see below), whose sum is σ = 71410961328. Its totient is φ = 71408668560.
The previous prime is 71409814907. The next prime is 71409814951. The reversal of 71409814943 is 34941890417.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 71409814943 - 210 = 71409813919 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 71409814891 and 71409814900.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (71409814043) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 474038 + ... + 606243.
It is an arithmetic number, because the mean of its divisors is an integer number (17852740332).
Almost surely, 271409814943 is an apocalyptic number.
71409814943 is a deficient number, since it is larger than the sum of its proper divisors (1146385).
71409814943 is a wasteful number, since it uses less digits than its factorization.
71409814943 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1146384.
The product of its (nonzero) digits is 870912, while the sum is 50.
The spelling of 71409814943 in words is "seventy-one billion, four hundred nine million, eight hundred fourteen thousand, nine hundred forty-three".
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