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72543517551161 = 73398967963917
BaseRepresentation
bin10000011111101001011010…
…100110000010101000111001
3100111212002111110121222120022
4100133221122212002220321
534002023110443114121
6414142010515540225
721165044664060446
oct2037513246025071
9314762443558508
1072543517551161
11211295954a7718
1281775052ba675
133162a941415c7
1413cb1a6d529cd
1585c053d15aab
hex41fa5a982a39

72543517551161 has 4 divisors (see below), whose sum is σ = 72642485515812. Its totient is φ = 72444549586512.

The previous prime is 72543517551139. The next prime is 72543517551163. The reversal of 72543517551161 is 16115571534527.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 40328596230400 + 32214921320761 = 6350480^2 + 5675819^2 .

It is a cyclic number.

It is not a de Polignac number, because 72543517551161 - 222 = 72543513356857 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (72543517551163) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 49483981226 + ... + 49483982691.

It is an arithmetic number, because the mean of its divisors is an integer number (18160621378953).

Almost surely, 272543517551161 is an apocalyptic number.

It is an amenable number.

72543517551161 is a deficient number, since it is larger than the sum of its proper divisors (98967964651).

72543517551161 is an equidigital number, since it uses as much as digits as its factorization.

72543517551161 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 98967964650.

The product of its digits is 4410000, while the sum is 53.

The spelling of 72543517551161 in words is "seventy-two trillion, five hundred forty-three billion, five hundred seventeen million, five hundred fifty-one thousand, one hundred sixty-one".

Divisors: 1 733 98967963917 72543517551161