Base | Representation |
---|---|
bin | 10000101101000111000011… |
… | …110011010110010001111011 |
3 | 100122010112120001210022002111 |
4 | 100231013003303112101323 |
5 | 34112202344324201203 |
6 | 420131015523513151 |
7 | 21321636614263513 |
oct | 2055070363262173 |
9 | 318115501708074 |
10 | 73468700615803 |
11 | 214559a0199729 |
12 | 82a68872287b7 |
13 | 31cc0b803b99c |
14 | 141dc92b36843 |
15 | 87615212626d |
hex | 42d1c3cd647b |
73468700615803 has 4 divisors (see below), whose sum is σ = 74226109900600. Its totient is φ = 72711291331008.
The previous prime is 73468700615777. The next prime is 73468700615833. The reversal of 73468700615803 is 30851600786437.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 73468700615803 - 233 = 73460110681211 is a prime.
It is a super-2 number, since 2×734687006158032 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (73468700615833) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 378704642253 + ... + 378704642446.
It is an arithmetic number, because the mean of its divisors is an integer number (18556527475150).
Almost surely, 273468700615803 is an apocalyptic number.
73468700615803 is a deficient number, since it is larger than the sum of its proper divisors (757409284797).
73468700615803 is an equidigital number, since it uses as much as digits as its factorization.
73468700615803 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 757409284796.
The product of its (nonzero) digits is 20321280, while the sum is 58.
The spelling of 73468700615803 in words is "seventy-three trillion, four hundred sixty-eight billion, seven hundred million, six hundred fifteen thousand, eight hundred three".
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