Base | Representation |
---|---|
bin | 100010010011010000… |
… | …0011111010000000101 |
3 | 21001010112012211211001 |
4 | 1010212200133100011 |
5 | 2201324041313403 |
6 | 53501132013301 |
7 | 5215242606211 |
oct | 1044640372005 |
9 | 231115184731 |
10 | 73660494853 |
11 | 2926a47a030 |
12 | 12338901231 |
13 | 6c3b918a3a |
14 | 37cac31941 |
15 | 1db1b71c1d |
hex | 112681f405 |
73660494853 has 8 divisors (see below), whose sum is σ = 83850682176. Its totient is φ = 64052604000.
The previous prime is 73660494851. The next prime is 73660494863. The reversal of 73660494853 is 35849406637.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 73660494853 - 21 = 73660494851 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 73660494794 and 73660494803.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (73660494851) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 145573848 + ... + 145574353.
It is an arithmetic number, because the mean of its divisors is an integer number (10481335272).
Almost surely, 273660494853 is an apocalyptic number.
It is an amenable number.
73660494853 is a deficient number, since it is larger than the sum of its proper divisors (10190187323).
73660494853 is a wasteful number, since it uses less digits than its factorization.
73660494853 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 291148235.
The product of its (nonzero) digits is 13063680, while the sum is 55.
The spelling of 73660494853 in words is "seventy-three billion, six hundred sixty million, four hundred ninety-four thousand, eight hundred fifty-three".
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