Base | Representation |
---|---|
bin | 100011111010111110… |
… | …1101110101100101011 |
3 | 21101010002111001200010 |
4 | 1013311331232230223 |
5 | 2230441101402021 |
6 | 55234344143003 |
7 | 5400425024643 |
oct | 1076575565453 |
9 | 241102431603 |
10 | 77141044011 |
11 | 2a796121139 |
12 | 12b4a467a63 |
13 | 7374a34b95 |
14 | 3a3b1a9523 |
15 | 20174da976 |
hex | 11f5f6eb2b |
77141044011 has 4 divisors (see below), whose sum is σ = 102854725352. Its totient is φ = 51427362672.
The previous prime is 77141044003. The next prime is 77141044033. The reversal of 77141044011 is 11044014177.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 77141044011 - 23 = 77141044003 is a prime.
It is a super-2 number, since 2×771410440112 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 77141044011.
It is not an unprimeable number, because it can be changed into a prime (77141044061) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12856840666 + ... + 12856840671.
It is an arithmetic number, because the mean of its divisors is an integer number (25713681338).
Almost surely, 277141044011 is an apocalyptic number.
77141044011 is a deficient number, since it is larger than the sum of its proper divisors (25713681341).
77141044011 is a wasteful number, since it uses less digits than its factorization.
77141044011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 25713681340.
The product of its (nonzero) digits is 3136, while the sum is 30.
Adding to 77141044011 its reverse (11044014177), we get a palindrome (88185058188).
The spelling of 77141044011 in words is "seventy-seven billion, one hundred forty-one million, forty-four thousand, eleven".
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