77740950253 has 4 divisors (see below), whose sum is σ = 77742750240. Its totient is φ = 77739150268.

The previous prime is 77740950239. The next prime is 77740950269. The reversal of 77740950253 is 35205904777.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-77740950253 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 77740950197 and 77740950206.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (77740950293) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 833575 + ... + 922132.

It is an arithmetic number, because the mean of its divisors is an integer number (19435687560).

Almost surely, 2^77740950253 is an apocalyptic number.

It is an amenable number.

77740950253 is a deficient number, since it is larger than the sum of its proper divisors (1799987).

77740950253 is a wasteful number, since it uses less digits than its factorization.

77740950253 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1799986.

The product of its (nonzero) digits is 1852200, while the sum is 49.

The spelling of 77740950253 in words is "seventy-seven billion, seven hundred forty million, nine hundred fifty thousand, two hundred fifty-three".