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79106216113 = 312551813423
BaseRepresentation
bin100100110101100011…
…0010001000010110001
321120012001022011000001
41021223012101002301
52244002142403423
6100201344430001
75500216512451
oct1115306210261
9246161264001
1079106216113
1130604440011
12133b8618301
1375c8c06902
143b86199d61
1520cecbdcad
hex126b1910b1

79106216113 has 4 divisors (see below), whose sum is σ = 81658029568. Its totient is φ = 76554402660.

The previous prime is 79106216099. The next prime is 79106216129. The reversal of 79106216113 is 31161260197.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31161260197 = 251124148447.

It is a de Polignac number, because none of the positive numbers 2k-79106216113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (79106216173) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1275906681 + ... + 1275906742.

It is an arithmetic number, because the mean of its divisors is an integer number (20414507392).

Almost surely, 279106216113 is an apocalyptic number.

It is an amenable number.

79106216113 is a deficient number, since it is larger than the sum of its proper divisors (2551813455).

79106216113 is a wasteful number, since it uses less digits than its factorization.

79106216113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2551813454.

The product of its (nonzero) digits is 13608, while the sum is 37.

The spelling of 79106216113 in words is "seventy-nine billion, one hundred six million, two hundred sixteen thousand, one hundred thirteen".

Divisors: 1 31 2551813423 79106216113