Base | Representation |
---|---|
bin | 111001111000101000100… |
… | …1000101011100001100001 |
3 | 1001011112220021110120000001 |
4 | 1303301101020223201201 |
5 | 2020321123002141423 |
6 | 24530434301300001 |
7 | 1450530122603434 |
oct | 163612110534141 |
9 | 31145807416001 |
10 | 7955640662113 |
11 | 2597a71829111 |
12 | a85a33b64601 |
13 | 4592a1647931 |
14 | 1d70ab13d81b |
15 | dbe278c7cad |
hex | 73c5122b861 |
7955640662113 has 4 divisors (see below), whose sum is σ = 8003279229120. Its totient is φ = 7908002095108.
The previous prime is 7955640662083. The next prime is 7955640662201. The reversal of 7955640662113 is 3112660465597.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-7955640662113 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (7955640662813) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23819283253 + ... + 23819283586.
It is an arithmetic number, because the mean of its divisors is an integer number (2000819807280).
Almost surely, 27955640662113 is an apocalyptic number.
It is an amenable number.
7955640662113 is a deficient number, since it is larger than the sum of its proper divisors (47638567007).
7955640662113 is a wasteful number, since it uses less digits than its factorization.
7955640662113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 47638567006.
The product of its (nonzero) digits is 8164800, while the sum is 55.
The spelling of 7955640662113 in words is "seven trillion, nine hundred fifty-five billion, six hundred forty million, six hundred sixty-two thousand, one hundred thirteen".
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