Base | Representation |
---|---|
bin | 111010010111010011001… |
… | …0010000100001111001001 |
3 | 1001101211212200120021001010 |
4 | 1310232212102010033021 |
5 | 2022411004341223213 |
6 | 25021005012314133 |
7 | 1455351043262301 |
oct | 164564622041711 |
9 | 31354780507033 |
10 | 8021493695433 |
11 | 2612995086799 |
12 | a96752012949 |
13 | 46256789453a |
14 | 1da3570a6601 |
15 | dd9cddd2ac3 |
hex | 74ba64843c9 |
8021493695433 has 64 divisors (see below), whose sum is σ = 12201584025600. Its totient is φ = 4663064609280.
The previous prime is 8021493695417. The next prime is 8021493695437. The reversal of 8021493695433 is 3345963941208.
It is not a de Polignac number, because 8021493695433 - 24 = 8021493695417 is a prime.
It is a super-2 number, since 2×80214936954332 (a number of 27 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (57).
It is not an unprimeable number, because it can be changed into a prime (8021493695437) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 2265085 + ... + 4601477.
It is an arithmetic number, because the mean of its divisors is an integer number (190649750400).
Almost surely, 28021493695433 is an apocalyptic number.
It is an amenable number.
8021493695433 is a deficient number, since it is larger than the sum of its proper divisors (4180090330167).
8021493695433 is a wasteful number, since it uses less digits than its factorization.
8021493695433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2336542.
The product of its (nonzero) digits is 16796160, while the sum is 57.
The spelling of 8021493695433 in words is "eight trillion, twenty-one billion, four hundred ninety-three million, six hundred ninety-five thousand, four hundred thirty-three".
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