Base | Representation |
---|---|
bin | 10010001111010010010100… |
… | …101110111100101001011111 |
3 | 101112000111201111100122212120 |
4 | 102033102110232330221133 |
5 | 41003221420431230403 |
6 | 442334222512234023 |
7 | 22616236011464454 |
oct | 2217222456745137 |
9 | 345014644318776 |
10 | 80215304555103 |
11 | 23617135238093 |
12 | 8bb631b23b913 |
13 | 359b369b31653 |
14 | 15b46274d782b |
15 | 9418b67d0e53 |
hex | 48f494bbca5f |
80215304555103 has 4 divisors (see below), whose sum is σ = 106953739406808. Its totient is φ = 53476869703400.
The previous prime is 80215304555069. The next prime is 80215304555137. The reversal of 80215304555103 is 30155540351208.
It is a semiprime because it is the product of two primes.
It is an interprime number because it is at equal distance from previous prime (80215304555069) and next prime (80215304555137).
It is a cyclic number.
It is not a de Polignac number, because 80215304555103 - 213 = 80215304546911 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (80215304555803) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13369217425848 + ... + 13369217425853.
It is an arithmetic number, because the mean of its divisors is an integer number (26738434851702).
Almost surely, 280215304555103 is an apocalyptic number.
80215304555103 is a deficient number, since it is larger than the sum of its proper divisors (26738434851705).
80215304555103 is a wasteful number, since it uses less digits than its factorization.
80215304555103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 26738434851704.
The product of its (nonzero) digits is 360000, while the sum is 42.
The spelling of 80215304555103 in words is "eighty trillion, two hundred fifteen billion, three hundred four million, five hundred fifty-five thousand, one hundred three".
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