80305011222133 has 4 divisors (see below), whose sum is σ = 84531590760160. Its totient is φ = 76078431684108.

The previous prime is 80305011222119. The next prime is 80305011222169. The reversal of 80305011222133 is 33122211050308.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 80305011222133 - 2⁴¹ = 78105987966581 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 80305011222095 and 80305011222104.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (80305011222103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2113289768985 + ... + 2113289769022.

It is an arithmetic number, because the mean of its divisors is an integer number (21132897690040).

Almost surely, 2^{80305011222133} is an apocalyptic number.

It is an amenable number.

80305011222133 is a deficient number, since it is larger than the sum of its proper divisors (4226579538027).

80305011222133 is a wasteful number, since it uses less digits than its factorization.

80305011222133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4226579538026.

The product of its (nonzero) digits is 8640, while the sum is 31.

The spelling of 80305011222133 in words is "eighty trillion, three hundred five billion, eleven million, two hundred twenty-two thousand, one hundred thirty-three".