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80560107253 = 394320431171
BaseRepresentation
bin100101100000111000…
…0011010111011110101
321200221101001110201001
41023001300122323311
52304441341413003
6101001522403301
75551232420233
oct1130160327365
9250841043631
1080560107253
1131190097a3a
1213743500531
13779b1a3922
143c832d9953
15216775b61d
hex12c1c1aef5

80560107253 has 4 divisors (see below), whose sum is σ = 80580542368. Its totient is φ = 80539672140.

The previous prime is 80560107241. The next prime is 80560107259. The reversal of 80560107253 is 35270106508.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 80560107253 - 221 = 80558010101 is a prime.

It is a super-2 number, since 2×805601072532 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (80560107259) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10211643 + ... + 10219528.

It is an arithmetic number, because the mean of its divisors is an integer number (20145135592).

Almost surely, 280560107253 is an apocalyptic number.

It is an amenable number.

80560107253 is a deficient number, since it is larger than the sum of its proper divisors (20435115).

80560107253 is a wasteful number, since it uses less digits than its factorization.

80560107253 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20435114.

The product of its (nonzero) digits is 50400, while the sum is 37.

The spelling of 80560107253 in words is "eighty billion, five hundred sixty million, one hundred seven thousand, two hundred fifty-three".

Divisors: 1 3943 20431171 80560107253