8067413481333 has 4 divisors (see below), whose sum is σ = 10756551308448. Its totient is φ = 5378275654220.

The previous prime is 8067413481319. The next prime is 8067413481389. The reversal of 8067413481333 is 3331843147608.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 8067413481333 - 2¹⁰ = 8067413480309 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (8067413481313) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1344568913553 + ... + 1344568913558.

It is an arithmetic number, because the mean of its divisors is an integer number (2689137827112).

Almost surely, 2^{8067413481333} is an apocalyptic number.

It is an amenable number.

8067413481333 is a deficient number, since it is larger than the sum of its proper divisors (2689137827115).

8067413481333 is a wasteful number, since it uses less digits than its factorization.

8067413481333 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2689137827114.

The product of its (nonzero) digits is 3483648, while the sum is 51.

The spelling of 8067413481333 in words is "eight trillion, sixty-seven billion, four hundred thirteen million, four hundred eighty-one thousand, three hundred thirty-three".