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806936049703 = 7216468082647
BaseRepresentation
bin10111011111000010010…
…00101111100000100111
32212010211202112120110101
423233201020233200213
5101210101112042303
61414411252004531
7112204425152200
oct13574110574047
92763752476411
10806936049703
112912463aa583
12110481300747
135b12ac515b4
142b0ad5d65a7
1515ecc1c7d1d
hexbbe122f827

806936049703 has 6 divisors (see below), whose sum is σ = 938680710936. Its totient is φ = 691659471132.

The previous prime is 806936049683. The next prime is 806936049719. The reversal of 806936049703 is 307940639608.

It is a de Polignac number, because none of the positive numbers 2k-806936049703 is a prime.

It is a super-2 number, since 2×8069360497032 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (806936049103) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 8234041275 + ... + 8234041372.

It is an arithmetic number, because the mean of its divisors is an integer number (156446785156).

Almost surely, 2806936049703 is an apocalyptic number.

806936049703 is a deficient number, since it is larger than the sum of its proper divisors (131744661233).

806936049703 is a wasteful number, since it uses less digits than its factorization.

806936049703 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 16468082661 (or 16468082654 counting only the distinct ones).

The product of its (nonzero) digits is 5878656, while the sum is 55.

The spelling of 806936049703 in words is "eight hundred six billion, nine hundred thirty-six million, forty-nine thousand, seven hundred three".

Divisors: 1 7 49 16468082647 115276578529 806936049703