Base | Representation |
---|---|
bin | 10010011010111001010110… |
… | …000110011111110001101011 |
3 | 101121211210000110111200012200 |
4 | 102122321112012133301223 |
5 | 41104304331111240442 |
6 | 444144525032311243 |
7 | 23031001402245510 |
oct | 2232712606376153 |
9 | 347753013450180 |
10 | 81013117680747 |
11 | 238a4519a177aa |
12 | 9104a75242523 |
13 | 36286729c3b15 |
14 | 16010ad23b307 |
15 | 95750caea34c |
hex | 49ae5619fc6b |
81013117680747 has 48 divisors (see below), whose sum is σ = 135101535279360. Its totient is φ = 45820785672000.
The previous prime is 81013117680739. The next prime is 81013117680751. The reversal of 81013117680747 is 74708671131018.
It is not a de Polignac number, because 81013117680747 - 23 = 81013117680739 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 81013117680693 and 81013117680702.
It is not an unprimeable number, because it can be changed into a prime (81013117682747) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 18783672 + ... + 22690362.
It is an arithmetic number, because the mean of its divisors is an integer number (2814615318320).
Almost surely, 281013117680747 is an apocalyptic number.
81013117680747 is a deficient number, since it is larger than the sum of its proper divisors (54088417598613).
81013117680747 is a wasteful number, since it uses less digits than its factorization.
81013117680747 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3910064 (or 3910061 counting only the distinct ones).
The product of its (nonzero) digits is 1580544, while the sum is 54.
The spelling of 81013117680747 in words is "eighty-one trillion, thirteen billion, one hundred seventeen million, six hundred eighty thousand, seven hundred forty-seven".
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