8124805051 has 4 divisors (see below), whose sum is σ = 8863423704. Its totient is φ = 7386186400.

The previous prime is 8124805021. The next prime is 8124805063. The reversal of 8124805051 is 1505084218.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 8124805051 - 2²⁷ = 7990587323 is a prime.

It is a super-3 number, since 3×8124805051³ (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 8124804998 and 8124805016.

It is not an unprimeable number, because it can be changed into a prime (8124805021) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 369309310 + ... + 369309331.

It is an arithmetic number, because the mean of its divisors is an integer number (2215855926).

Almost surely, 2^8124805051 is an apocalyptic number.

8124805051 is a deficient number, since it is larger than the sum of its proper divisors (738618653).

8124805051 is a wasteful number, since it uses less digits than its factorization.

8124805051 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 738618652.

The product of its (nonzero) digits is 12800, while the sum is 34.

The square root of 8124805051 is about 90137.7004976275. The cubic root of 8124805051 is about 2010.3468004692.

Adding to 8124805051 its reverse (1505084218), we get a palindrome (9629889269).

The spelling of 8124805051 in words is "eight billion, one hundred twenty-four million, eight hundred five thousand, fifty-one".