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8130427503473 = 11739129773043
BaseRepresentation
bin111011001010000001100…
…1111100100001101110001
31001210021001110202002000002
41312110003033210031301
52031202103420102343
625143022234035345
71466255400335342
oct166240317441561
931707043662002
108130427503473
112655105403020
12ab3893878b55
1346c908219b12
1420172c82c0c9
15e17575c18b8
hex765033e4371

8130427503473 has 4 divisors (see below), whose sum is σ = 8869557276528. Its totient is φ = 7391297730420.

The previous prime is 8130427503463. The next prime is 8130427503533. The reversal of 8130427503473 is 3743057240318.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 8130427503473 - 218 = 8130427241329 is a prime.

It is a super-2 number, since 2×81304275034732 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (8130427503413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 369564886511 + ... + 369564886532.

It is an arithmetic number, because the mean of its divisors is an integer number (2217389319132).

Almost surely, 28130427503473 is an apocalyptic number.

It is an amenable number.

8130427503473 is a deficient number, since it is larger than the sum of its proper divisors (739129773055).

8130427503473 is a wasteful number, since it uses less digits than its factorization.

8130427503473 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 739129773054.

The product of its (nonzero) digits is 1693440, while the sum is 47.

The spelling of 8130427503473 in words is "eight trillion, one hundred thirty billion, four hundred twenty-seven million, five hundred three thousand, four hundred seventy-three".

Divisors: 1 11 739129773043 8130427503473