Base | Representation |
---|---|
bin | 100101110111011000… |
… | …0111000001010100111 |
3 | 21202212222220020120011 |
4 | 1023232300320022213 |
5 | 2313013142423303 |
6 | 101204454551051 |
7 | 5606031544621 |
oct | 1135660701247 |
9 | 252788806504 |
10 | 81315201703 |
11 | 3153834763a |
12 | 13914368487 |
13 | 788b763188 |
14 | 3d156d5c11 |
15 | 21adbb316d |
hex | 12eec382a7 |
81315201703 has 4 divisors (see below), whose sum is σ = 86098448880. Its totient is φ = 76531954528.
The previous prime is 81315201599. The next prime is 81315201731. The reversal of 81315201703 is 30710251318.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-81315201703 is a prime.
It is a super-2 number, since 2×813152017032 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (81315201503) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2391623563 + ... + 2391623596.
It is an arithmetic number, because the mean of its divisors is an integer number (21524612220).
Almost surely, 281315201703 is an apocalyptic number.
81315201703 is a deficient number, since it is larger than the sum of its proper divisors (4783247177).
81315201703 is a wasteful number, since it uses less digits than its factorization.
81315201703 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4783247176.
The product of its (nonzero) digits is 5040, while the sum is 31.
The spelling of 81315201703 in words is "eighty-one billion, three hundred fifteen million, two hundred one thousand, seven hundred three".
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