Base | Representation |
---|---|
bin | 111011001100010100111… |
… | …1101010111111100100011 |
3 | 1001210201211001201012102102 |
4 | 1312120221331113330203 |
5 | 2031242220213411342 |
6 | 25145201024041015 |
7 | 1466522050101125 |
oct | 166305175277443 |
9 | 31721731635372 |
10 | 8135372013347 |
11 | 265721245a517 |
12 | ab483376316b |
13 | 47021571a3c7 |
14 | 201a7b3a7215 |
15 | e1946716832 |
hex | 76629f57f23 |
8135372013347 has 4 divisors (see below), whose sum is σ = 8152943011680. Its totient is φ = 8117801015016.
The previous prime is 8135372013313. The next prime is 8135372013407. The reversal of 8135372013347 is 7433102735318.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 8135372013347 - 212 = 8135372009251 is a prime.
It is a super-3 number, since 3×81353720133473 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (8135372013047) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8785498472 + ... + 8785499397.
It is an arithmetic number, because the mean of its divisors is an integer number (2038235752920).
Almost surely, 28135372013347 is an apocalyptic number.
8135372013347 is a deficient number, since it is larger than the sum of its proper divisors (17570998333).
8135372013347 is a wasteful number, since it uses less digits than its factorization.
8135372013347 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 17570998332.
The product of its (nonzero) digits is 1270080, while the sum is 47.
The spelling of 8135372013347 in words is "eight trillion, one hundred thirty-five billion, three hundred seventy-two million, thirteen thousand, three hundred forty-seven".
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