Base | Representation |
---|---|
bin | 10010110010011110111111… |
… | …001010110111001010000101 |
3 | 101211120202000022220222021221 |
4 | 102302132333022313022011 |
5 | 41312334100233301430 |
6 | 451425323531040341 |
7 | 23256054420065623 |
oct | 2262367712671205 |
9 | 354522008828257 |
10 | 82634083103365 |
11 | 24369a10711542 |
12 | 93270572a00b1 |
13 | 371548c316371 |
14 | 165972211a513 |
15 | 98477ea9b57a |
hex | 4b27bf2b7285 |
82634083103365 has 16 divisors (see below), whose sum is σ = 104994210629952. Its totient is φ = 62218416012544.
The previous prime is 82634083103359. The next prime is 82634083103527. The reversal of 82634083103365 is 56330138043628.
It is a cyclic number.
It is not a de Polignac number, because 82634083103365 - 25 = 82634083103333 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 31097442 + ... + 33649948.
It is an arithmetic number, because the mean of its divisors is an integer number (6562138164372).
Almost surely, 282634083103365 is an apocalyptic number.
82634083103365 is a gapful number since it is divisible by the number (85) formed by its first and last digit.
It is an amenable number.
82634083103365 is a deficient number, since it is larger than the sum of its proper divisors (22360127526587).
82634083103365 is a wasteful number, since it uses less digits than its factorization.
82634083103365 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2933396.
The product of its (nonzero) digits is 7464960, while the sum is 52.
The spelling of 82634083103365 in words is "eighty-two trillion, six hundred thirty-four billion, eighty-three million, one hundred three thousand, three hundred sixty-five".
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