Base | Representation |
---|---|
bin | 11000001010001010100… |
… | …11110000111010011011 |
3 | 2221100121111121011210210 |
4 | 30011011103300322123 |
5 | 102100011410401430 |
6 | 1433201101342203 |
7 | 113654304210216 |
oct | 14050523607233 |
9 | 2840544534723 |
10 | 830091497115 |
11 | 2a0049011981 |
12 | 114a63b67963 |
13 | 6037b298c7a |
14 | 2c2689ca77d |
15 | 168d4e912b0 |
hex | c1454f0e9b |
830091497115 has 16 divisors (see below), whose sum is σ = 1406272654368. Its totient is φ = 416673378816.
The previous prime is 830091497093. The next prime is 830091497117. The reversal of 830091497115 is 511794190038.
It is not a de Polignac number, because 830091497115 - 212 = 830091493019 is a prime.
It is not an unprimeable number, because it can be changed into a prime (830091497117) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1627630132 + ... + 1627630641.
It is an arithmetic number, because the mean of its divisors is an integer number (87892040898).
Almost surely, 2830091497115 is an apocalyptic number.
830091497115 is a gapful number since it is divisible by the number (85) formed by its first and last digit.
830091497115 is a deficient number, since it is larger than the sum of its proper divisors (576181157253).
830091497115 is a wasteful number, since it uses less digits than its factorization.
830091497115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3255260798.
The product of its (nonzero) digits is 272160, while the sum is 48.
The spelling of 830091497115 in words is "eight hundred thirty billion, ninety-one million, four hundred ninety-seven thousand, one hundred fifteen".
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