Base | Representation |
---|---|
bin | 10010111001010000111011… |
… | …110001001110000000000011 |
3 | 101220020021200222012212011200 |
4 | 102321100323301032000003 |
5 | 41343002330140014110 |
6 | 452423343214112243 |
7 | 23334531132265026 |
oct | 2271207361160003 |
9 | 356207628185150 |
10 | 83100030001155 |
11 | 24529585582262 |
12 | 93a1413aab683 |
13 | 374a3b74771cb |
14 | 16740c48bb1bd |
15 | 991950d416c0 |
hex | 4b943bc4e003 |
83100030001155 has 24 divisors (see below), whose sum is σ = 144262679644512. Its totient is φ = 44251515187584.
The previous prime is 83100030001123. The next prime is 83100030001211. The reversal of 83100030001155 is 55110003000138.
It is not a de Polignac number, because 83100030001155 - 25 = 83100030001123 is a prime.
It is a super-2 number, since 2×831000300011552 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1427070834 + ... + 1427129063.
It is an arithmetic number, because the mean of its divisors is an integer number (6010944985188).
Almost surely, 283100030001155 is an apocalyptic number.
83100030001155 is a deficient number, since it is larger than the sum of its proper divisors (61162649643357).
83100030001155 is a wasteful number, since it uses less digits than its factorization.
83100030001155 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2854200555 (or 2854200552 counting only the distinct ones).
The product of its (nonzero) digits is 1800, while the sum is 27.
The spelling of 83100030001155 in words is "eighty-three trillion, one hundred billion, thirty million, one thousand, one hundred fifty-five".
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