Base | Representation |
---|---|
bin | 10010111001010001111100… |
… | …110000100010001010100111 |
3 | 101220020101111221212211202211 |
4 | 102321101330300202022213 |
5 | 41343012043301400042 |
6 | 452424043323544251 |
7 | 23334600142104253 |
oct | 2271217460421247 |
9 | 356211457784684 |
10 | 83101120340647 |
11 | 24529a94a99482 |
12 | 93a167908b087 |
13 | 374a52c3249c6 |
14 | 1674189623263 |
15 | 9919b691a017 |
hex | 4b947cc222a7 |
83101120340647 has 8 divisors (see below), whose sum is σ = 84271733288352. Its totient is φ = 81930512244000.
The previous prime is 83101120340633. The next prime is 83101120340659. The reversal of 83101120340647 is 74604302110138.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 83101120340647 - 243 = 74305027318439 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (83101120340047) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 46317397 + ... + 48078097.
It is an arithmetic number, because the mean of its divisors is an integer number (10533966661044).
Almost surely, 283101120340647 is an apocalyptic number.
83101120340647 is a deficient number, since it is larger than the sum of its proper divisors (1170612947705).
83101120340647 is a wasteful number, since it uses less digits than its factorization.
83101120340647 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2425529.
The product of its (nonzero) digits is 96768, while the sum is 40.
The spelling of 83101120340647 in words is "eighty-three trillion, one hundred one billion, one hundred twenty million, three hundred forty thousand, six hundred forty-seven".
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