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834103436143 = 4176119973263
BaseRepresentation
bin11000010001101000111…
…00000110001101101111
32221201222002202210112011
430020310130012031233
5102131220434424033
61435103135222051
7114155601140365
oct14106434061557
92851862683464
10834103436143
112a181771006a
121157a3677927
136086a50a9a3
142c52976b635
1516a6c2c3ccd
hexc23470636f

834103436143 has 4 divisors (see below), whose sum is σ = 834123451168. Its totient is φ = 834083421120.

The previous prime is 834103436141. The next prime is 834103436161. The reversal of 834103436143 is 341634301438.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 834103436143 - 21 = 834103436141 is a prime.

It is an alternating number because its digits alternate between even and odd.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 834103436096 and 834103436105.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (834103436141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9944871 + ... + 10028392.

It is an arithmetic number, because the mean of its divisors is an integer number (208530862792).

Almost surely, 2834103436143 is an apocalyptic number.

834103436143 is a deficient number, since it is larger than the sum of its proper divisors (20015025).

834103436143 is a wasteful number, since it uses less digits than its factorization.

834103436143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20015024.

The product of its (nonzero) digits is 248832, while the sum is 40.

The spelling of 834103436143 in words is "eight hundred thirty-four billion, one hundred three million, four hundred thirty-six thousand, one hundred forty-three".

Divisors: 1 41761 19973263 834103436143