Base | Representation |
---|---|
bin | 1011111100000100111001110… |
… | …0011111001011110100110111 |
3 | 11002011120211121221221211012012 |
4 | 2333001032130133023310313 |
5 | 1340103340030013420322 |
6 | 12134433414552314435 |
7 | 341646011363300615 |
oct | 27701163437136467 |
9 | 4064524557854165 |
10 | 840111113420087 |
11 | 22375a138968463 |
12 | 7a2831b40a2a1b |
13 | 2a0a01a442c2c2 |
14 | 10b658483846b5 |
15 | 671d340ba8ae2 |
hex | 2fc139c7cbd37 |
840111113420087 has 4 divisors (see below), whose sum is σ = 840145274023440. Its totient is φ = 840076952816736.
The previous prime is 840111113420083. The next prime is 840111113420093. The reversal of 840111113420087 is 780024311111048.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 840111113420087 - 22 = 840111113420083 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (840111113420083) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17080264787 + ... + 17080313972.
It is an arithmetic number, because the mean of its divisors is an integer number (210036318505860).
Almost surely, 2840111113420087 is an apocalyptic number.
840111113420087 is a deficient number, since it is larger than the sum of its proper divisors (34160603353).
840111113420087 is a wasteful number, since it uses less digits than its factorization.
840111113420087 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 34160603352.
The product of its (nonzero) digits is 43008, while the sum is 41.
The spelling of 840111113420087 in words is "eight hundred forty trillion, one hundred eleven billion, one hundred thirteen million, four hundred twenty thousand, eighty-seven".
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