Base | Representation |
---|---|
bin | 100111101000111100… |
… | …0000001010111100001 |
3 | 22010201112122120112102 |
4 | 1033101320001113201 |
5 | 2343314112034213 |
6 | 103034530540145 |
7 | 6102326555246 |
oct | 1172170012741 |
9 | 263645576472 |
10 | 85125502433 |
11 | 33113143a04 |
12 | 145b8437655 |
13 | 8047c95caa |
14 | 41977895cd |
15 | 2333466158 |
hex | 13d1e015e1 |
85125502433 has 4 divisors (see below), whose sum is σ = 85151641860. Its totient is φ = 85099363008.
The previous prime is 85125502417. The next prime is 85125502439. The reversal of 85125502433 is 33420552158.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 35371077184 + 49754425249 = 188072^2 + 223057^2 .
It is a cyclic number.
It is not a de Polignac number, because 85125502433 - 24 = 85125502417 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (85125502439) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13064828 + ... + 13071341.
It is an arithmetic number, because the mean of its divisors is an integer number (21287910465).
Almost surely, 285125502433 is an apocalyptic number.
It is an amenable number.
85125502433 is a deficient number, since it is larger than the sum of its proper divisors (26139427).
85125502433 is a wasteful number, since it uses less digits than its factorization.
85125502433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 26139426.
The product of its (nonzero) digits is 144000, while the sum is 38.
The spelling of 85125502433 in words is "eighty-five billion, one hundred twenty-five million, five hundred two thousand, four hundred thirty-three".
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